C8060-350問題集、IBM実際の試験問題

質問 1

One way to modify a type tree in order to increase performance is to:

A. reduce the number of categories whenever necessary.

B. join referenced text fields and then use the Substring map function.

C. eliminate the specification of groups when not necessary.

D. reduce the length of the names of groups and elements.

正解: C

質問 2

The example here shows three records of a file. Each record is terminated with a <NL> character. The file is not limited to a specific number of records.
CMS Business Systems S30093467390212200815AN<NL>
CMS Business Systems S40073617390628200817NN<NL>
CMS Business Systems S40073617390628200817NN<NL>
The type tree has been constructed with two groups named File and Record.
Which of the following options BEST defines the format and component syntax properties for the two groups?

A. The File component is defined as Format = Explicit and Component Syntax = Fixed; the Record component is defined as Format = Explicit and Component Syntax = Fixed

B. The File component is defined as Format = Implicit and Component Syntax = Fixed; the Record component is defined as Format = Implicit and Component Syntax = None

C. The File component is defined as Format = Explicit and Component Syntax = None; the Record component is defined as Format = Explicit and Component Syntax = None

D. The File component is defined as Format = Implicit and Component Syntax = None; the Record component is defined as Format = Explicit and Component Syntax = Fixed.

正解: D

質問 3

The following map rule returns the incorrect results; however, the map rule does return the expected results when each LOOKUP is run independently.
=IF(PRESENT(Name:.:AddressFile), LOOKUP(Record:input,Field1 Field:Record:input="aa"), LOOKUP(Record:input,Field1 Field:Record:input="cc"))
Why does the rule return the INCORRECT results?

A. The syntax of the object name Name:.:AddressFile is incorrect.

B. IF(PRESENT) was used instead of WHEN(PRESENT).

C. Two LOOKUPs are not allowed in a single map rule.

D. Both LOOKUPs reference the same series object.

正解: D

質問 4

An application developer has a file which consists of fixed length records. The first record is a header record followed by some number of detail records. The number of detail records is expressed by a value found in the header record. How does the developer define this type of data in WebSphere Transformation Extender?

A. Write a custom function to store the number of detail records in the map context.

B. Index the input based on the count in the header record.

C. Use a component rule to compare the current record to the value found in the header.

D. Use a Map function to keep track of how many detail records there are.

正解: C

質問 5

An application developer needs to split a file consisting of 10 records into 10 output files each with one record. The file name of the output files must contain the record number from the input file. Which two functions can be used in this map to achieve this task?

A. COUNT and CREATEFILE

B. INDEX and RUN

C. INDEX and SETFILENAME

D. CHOOSE and GETANDSET

正解: B

質問 6

Out of all the available settings for the location of the workspace, which of the following is the MOST OPTIMAL setting for performance when processing small transactions such as MQ messages?

A. Workspace = Burst

B. Workspace = Page

C. Workspace = Memory

D. Workspace = File

正解: C

質問 7

Refer to the image shown here:

Which map rule function takes the MOST time to run?

A. LOOKUP

B. TYPE_NAME

C. BUILD_CARD

D. MAP_NAME

正解: A

IBM WebSphere Transformation Extender V8.4, Application Development - C8060-350 模擬練習